Four rolls

You roll a fair six-sided die 4 times. What is the probability of getting at least one six?

Hint

It is easier to count the opposite event.

Solution

The complement is “no sixes in 4 rolls”: $(5/6)^4$.

$1 - \left(\tfrac{5}{6}\right)^4 = \tfrac{671}{1296}$

Answer

$\approx 0.518$